Please help, i'll give brainliest and a lot of points :) Triangle ABC has vertices A(2,3), B(4,5), and C(6,1).

If ΔABC is dilated by a scale factor of 3/2
and has the origin as the center of dilation, what are the coordinates of B'?

A) B' (9, 3/2)
B) B' (5 1/2, 6 1/2)
C) B' (6, 15/2)
D) B' (3, 4.5)

I can't answer your question but get an idea of this

Step-by-step explanation:

If ΔABC is dilated by a scale factor of 1/2

with a dilation center of A, what will be the coordinates of point C'?

Point C is at (2,0)

Cut each coordinate in half to get (1,0)

2*(1/2) = 1

0*(1/2) = 0

So point C will move to (1,0)

Not the answer but an example on how to do it

according to the triangle sum theorem, all the angles in a triangle must add up to 180 degrees. if we know one angle is already 90, we do 180-90=90. the other 2 angles must add up to 90, exactly.

step-by-step explanation: