ABC and AMN are similar triangles AM=6cm MB=4cm and the area of∆AMN (a)find the area of∆ABC (b)find the area of MNCB​

the correct answer is b) histograms can be used to exhibit the shape of distributions. this is because histograms count the frequency of each possible answer, so one is able to see which results are more common and which are less common.

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it

i think it will be zero as slope has a formula of difference between initial and final distance divided by itz time interval

a rotation about point l

step-by-step explanation:

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