12, 17, 22... find the 35th term

a₃₅ = 182

Step-by-step explanation:

There is a common difference d between consecutive terms, that is

d = 17 - 12 = 22 - 17 = 5

This indicates the sequence is arithmetic with n th term

= a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 12 and d = 5 , then

a₃₅ = 12 + (34 × 5) = 12 + 170 = 182

a

step-by-step explanation:

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