The sine of acute angle A in the triangle ABC is given by the ratio sinA = length of leg opposite angle A / length of hypothenuse = BC/AB since 0
the same argument shows that 0

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

time is equal to distance over rate so

t = d/r

need a little bit more information for the second question.