A person invests $2,730 in an account that earns 4.2% annual interest. Find when the value of the investment reaches $5,000. If necessary, round to the nearest tenth.

Step-by-step explanation:

You want to calculate the interest on $2730 at 4.2% interest per year after 5,000 year(s).

The formula we'll use for this is the simple interest formula, or:

Where:P is the principal amount, $2730.00.

r is the interest rate, 4.2% per year, or in decimal form, 4.2/100=0.042.

t is the time involved, 5year(s) time periods.

So, t is 5year time periods.

To find the simple interest, we multiply 2730 × 0.042 × 5 to get that:

The interest is: $573.30

the solution of the equation is 2.23 ⇒ answer b

step-by-step explanation:

* lets revise the meaning of exponential function

- the form of the exponential function is y = ab^x, where a ≠ 0, b > 0 ,  

  b ≠ 1, and x is any real number

- it has a constant base b

- it has a variable exponent x

- to solve an exponential equation, take the log or ln of both sides,  

  and solve for the variable

* lets solve the problem

∵

- the base is 7 and the exponent is x

- insert ㏑ in both sides

∴

- use the rule

∴ x ㏑(7) = ㏑(77)

- to find x divide both sides by ㏑(7)

∴

* the solution of the equation is 2.23 to the nearest 2 decimal places

25/14 or 1.

step-by-step explanation:

the dots mean that it has infinitely more numbers behind it