The function y=h(x) is defined as follows: h (x) ={x^2 for x<0 ,3-x for 0≤x<1, x^3 for 1≤x≤3, 5 for x>3
h(1)= and h(4)= ​

h(1) = 1

h(4) = 5

Step-by-step explanation:

Since 1 is in the interval 1 ≤ x ≤ 3, you must substitute 1 into the expression  

So, h(1) = = 1

Since 4 is in the interval x > 3, and all values of x > 3 gives an output of 5, then h(4) = 5

i do not know this sorry : (

answer: 12

step-by-step explanation:

because yes