(order doesn't matter)

Because there are 4 ways to pick red then 4 (C)

Possible outcomes that contain at least one red tile = 7

Step-by-step explanation:

Number of blue tile = 1

Number of green tile = 1

Number of red tile = 1

Number of yellow tile = 1

Total number of tiles = 4

Possible number of outcomes in choosing one tile = 4

Possible number of outcomes in selecting the second tile = 4

⇒ Possible number of outcomes in selecting both the tiles = 4 × 4 = 16

We need to find the find the possible outcomes that contain at least one red ⇒ One tile must be at least of red color.

Now, Possible outcomes of selecting first tile if not red = 3

Possible outcomes of selecting second tile if not red = 3

⇒ Possible outcomes of selecting both the tiles if not red = 3 × 3 = 9

Hence, Possible outcomes that contain at least one red tile = 16 - 9 = 7

Here's an another way to answer this question:

How many ways can we pick a tile and then a red tile

4* 1  = 4   (this approach gives us the red-red combo

and how many was can we pick a red and then a non red

1*3 = 3

now we combine these to get the 7 possible choices with red

usually it is easier to solve these type of problems using the first approach that I illustrated.

step-by-step explanation:

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hope this !