A cone has a height of 15 inches and a radius of 12 inches. What is its volume?

V ≈ 7186 in³

Step-by-step explanation:

The volume of a cone of base radius r and height h is V = (1/3)(π)(r^2)(h).

When h = 15 in and r = 12 in, the volume of the cone is

V = (1/3)(π)(12 in)²·(15 in), or approximately V ≈ 7186 in³

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

step-by-step explanation:

∆abc has the points a(1, 7), b(-2, 2), and c(4, 2) as its vertices. formed with the point d(1, 2) as its third vertex, then ∆abd is triangle.