The function f is continuous on the closed interval closed interval from pi over 3 to 5 times pi all over 3.. Selected values of f are given in the table: x pi over 3 | 2 times pi all over 3 | 4 times pi all over 3 | 5 times pi all over 3
f(x) 0.4775 | −0.2387 | −0.1194. | k

What value of k in the table would give the equation f(x) = 0 at least two solutions in the interval closed interval from pi over 3 to 5 times pi all over 3?

negative pi over 3
−0.0955
0.0955
negative 5 times pi all over 3

6 spoons of sugar for every 21 cups of flour

step-by-step explanation:

step-by-step explanation:

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y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )