The function f is continuous where f(−5) = −1 and f(5) = 6, and g is a function defined by g(x) = 1 − (f(x))2. Is there a value c for −5 < c < 5 such that g(c) = 1? Why, or why not? Yes; the function g is continuous
Yes; g(−5) < 1 < g(5), so IVT guarantees there is a value c for −5 < c < 5 such that g(c) = 1
No; 1 is not between g(−5) and g(5), so IVT cannot guarantee there is a value c for −5 < c < 5 such that g(c) = 1
No; the function g is not continuous

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