A rectangle has a perimeter of 30 inches. Its length is one less than three times its width. What is the width of the rectangle?

Perimeter of a rectangle can be represented by 2* length + 2 * width

We can represent the width with the variable x

We can represent the length by the expression 3x-1

So, now we can make a forumla and solve

2(3x-1) + 2(x) = 30

6x-2+2x = 30

8x = 32

x = 4 is the width of the rectange.

Now we find the length

3(4)-1

11 = Length

4

Step-by-step explanation:

The length is 3w-1. The perimeter isn't large enough for the width to be anything more than 10. I just used the number 4. 4 times 3 equals 12. 12 minus 1 equals 11. So to find the perimeter we have to add all the side lengths together. So 11 plus 11 equals 22. 4 plus 4 equals 8. 22 plus 8 equals 30. The answer is 4.

the answer is b

its line 2 i just added the rest or else it wouldn't let me answer