Plz help this is an exam thx Figure ABCDE has vertices A(−3, 3), B(2, 3), C(5, −2), D(0, −3), and E(−3, −2). Plot the points on your own coordinate grid and connect the points in alphabetical order. Decompose Figure ABCDE into rectangles and triangles. Part A: How many triangles and rectangles did you make? (1 point)

Part B: Use Figure ABCDE created on your coordinate grid to find the lengths, in units, of Sides AB and AE. (4 points)

Part C: What is the area of Figure ABCDE? Show your work.

What there saying is basically find a cordinate grid and plot the points and then connect it and its gonna give you a shape.

remeber: the x axis goes first then the y axis.

dont wanna do the work? i got youuuu

this pic is basiclly what is is.

Part A: I got 3 triangles if u see more just add them in and then 1 rectangle

Part B: count the units which for Ab would be 4 and Ae would be 5

Part c: cut the shape in half so it would be 2 rectangles and first rectangle would be the area of 20 and the other one 12 and then add it toegther and it would be 32

have a great day and sorry for it being late i was also doing test again cause i failed it and i finally understand lol

have a great day <333

1 liter of pineapple juice was made i think.

step-by-step explanation:

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.