A bag contains 11 milk and 7 dark chocolates. A sweet is selected at random. What is the probability of choosing: P(milk) = P(not milk) =

Milk = 61%   Not milk = 39%

Step-by-step explanation:

There are 18 total chocolates in the bag.

Milk:

11/18 · x/100

1. 18 · x = 18x

2. 11 · 100 = 1100

Now we have 18x = 1100

3. 1100 ÷ 18 = 61.1...

4. Round

Milk = 61%

Not milk:

7/18 · x/100

1. 18 · x = 18x

2. 7 · 100 = 700

Now we have 18x = 700

3. 700 ÷ 18 = 38.89

4. Round

Not milk = 39%

idk i would have to be there to under stand it

step-by-step explanation:

idk i would have to be there to under stand it