Solve for x round to the nearest tenth

19.2

Step-by-step explanation:

use the Pythagorean theorem a^2+b^2=c^2

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so:

answer: hey there,

the answer you are looking for is a..

hope this you!