Mathematics, 12.03.2021 20:40 Luis2737

In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor in television ads in the United States and the United Kingdom. They found that a substantially greater percentage of U. K. ads use humor. (a) Suppose that a random sample of 400 television ads in the United Kingdom reveals that 147 of these ads use humor. Find a point estimate of and a 95 percent confidence interval for the proportion of all U. K. television ads that use humor. (Round your answers to 3 decimal places.) (b) Suppose a random sample of 455 television ads in the United States reveals that 119 of these ads use humor. Find a point estimate of and a 95 percent confidence interval for the proportion of all U. S. television ads that use humor. (Round your answers to 3 decimal places.) (c) Do the confidence intervals you computed in parts a and b suggest that a greater percentage of U. K. ads use humor

Answers: 2

Show answers

Answers

Answer from: jonmorton159

The point estimate is 0.368.

The 95 percent confidence interval for the proportion of all U.K. television ads that use humor is (0.321, 0.415).

The point estimate is 0.262.

The 95 percent confidence interval for the proportion of all U.S. television ads that use humor is (0.222, 0.302).

Yes, because the lower bound of the confidence interval for UK proportions is higher than the upper bound of the confidence interval for US proportions.

Step-by-step explanation:

(a) Suppose that a random sample of 400 television ads in the United Kingdom reveals that 147 of these ads use humor.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

Sample of 400:

This means that n = 400

Point estimate:

$\pi = \frac{147}{400} = 0.368$

The point estimate is 0.368.

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so Z = 1.96 .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.368 - 1.96\sqrt{\frac{0.368*0.632}{400}} = 0.321$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.368 + 1.96\sqrt{\frac{0.368*0.632}{400}} = 0.415$

The 95 percent confidence interval for the proportion of all U.K. television ads that use humor is (0.321, 0.415).

(b) Suppose a random sample of 455 television ads in the United States reveals that 119 of these ads use humor.

Sample of 455:

This means that n = 455

Point estimate:

$\pi = \frac{119}{455} = 0.262$

The point estimate is 0.262.

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so Z = 1.96 .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.262 + 1.96\sqrt{\frac{0.262*0.738}{455}} = 0.222$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.262 + 1.96\sqrt{\frac{0.262*0.738}{455}} = 0.302$

The 95 percent confidence interval for the proportion of all U.S. television ads that use humor is (0.222, 0.302).

Yes, because the lower bound of the confidence interval for UK proportions is higher than the upper bound of the confidence interval for US proportions.

Answer from: Quest

the graph in the attached figure

step-by-step explanation:

we have

$f(x)=2x^{3}-7x^{2} +2x+3$

using a graphing tool

the graph in the attached figure

the roots are ( x-intercepts) x=-0.5,x=1,x=3

the y-intercept is the point (0,3)

Answer from: Quest

The correct answer is 10%

Another question on Mathematics

Mathematics, 21.06.2019 13:10

Aresearch company wants to test the claim that a new multivitamin to improve short term memory. state the objective of the experiment, suggest a population, determine the experimental and control groups, and describe a sample procedure.

Answers: 2

Answer

Mathematics, 21.06.2019 16:30

Which statement about perfect cubes is true

Answers: 1

Answer

Mathematics, 21.06.2019 21:00

25 ! i need asap! ! ill mark brainliest!

Answers: 2

Answer

Mathematics, 21.06.2019 22:00

Luke started a weight-loss program. the first week, he lost x pounds. the second week, he lost pounds less than times the pounds he lost the first week. the third week, he lost 1 pound more than of the pounds he lost the first week. liam started a weight-loss program when luke did. the first week, he lost 1 pound less than times the pounds luke lost the first week. the second week, he lost 4 pounds less than times the pounds luke lost the first week. the third week, he lost pound more than times the pounds luke lost the first week.

Answers: 2

Answer

You know the right answer?

In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor in telev...

Questions