At the theater, the Seward family bought 2 adult tickets and 3 children's tickets for $44.50. The Sena family bought 3 adult tickets and 6 children's tickets for $78. Find the price of an adult ticket and the price of a child's ticket.

Adult ticket is $7.5 while a child's ticket is $11

Step-by-step explanation:

Given data

Let the cost of an adult ticket be x

and the cost of a child ticket be y

The Seward family

2x+3y= 44.501

The Sena family

3x+6y= 782

solve 1 and 2

2x+3y= 44.50   X2

3x+6y= 78        X1

   4x+6y= 89

- 3x+6y= 78

  x+ 0= 11

x= 11

put x= 11 in 1

2x+3y= 44.50

2*11+3y= 44.5

22+3y=44.5

3y= 44.5-22

3y= 22.5

y= 22.5/3

y= 7.5

Hence Adult ticket is $7.5 while a child's ticket is $11

see explanation

step-by-step explanation:

a

(6r + 7) + (13 + 7r) ( remove brackets and collect like terms )

= 6r + 7 + 13 + 7r

= 13r + 20

b

remove brackets and collect like terms

13 - r - 1 + r

= 12 - r

c

remove brackets and collect like terms

= - 8 - r + 2r - 4

= - 12 + r

d

remove brackets and collect like terms

= 7r - - - 6r

[-   - = - - = - ]

= r -

that one look

step-by-step explanation: