a piece of work can be completed in 30 days by 10 men. if the work is to be completed 5 days earlier, how many more men are needed? (assume that the men work at the same rate)

so, if 10 men can do it In 30 days, that means a total of 300 "man days".

300 man days divided by 25 days would be 12- so 2 more men.

answer: 59

step-by-step explanation:

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.