The probability of getting heads on a single coin flip is 1
2
. The probability of getting nothing but heads on a series of coin flips decreases by
1
2
for each additional coin flip. Enter an exponential function for the probability p(n) of getting all heads in a series of n coin flips. Give your answer in the form a(b)n. In the event that a = 1, give your answer in the form (b)n.

The equation is p(n) = .

I hope this helps :D

Step-by-step explanation:

4

It can be done a lot easier: instead of calculating the probability of one head, two heads, three heads, ... one just needs to calculate the probability of no heads: that is simply 0.5

0.5

n

. If you subtract it from 1, you get the probability you want: it's because that's the chance of not no heads, meaning at least one head. So, the formula is: 1−0.5

1

−

0.5

n

More formally: if X is throwing at least one head,

()=1−(¬)

P

(

X

)

=

1

−

P

(

¬

X

)

, where ¬

¬

X

is throwing zero heads.

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step-by-step explanation:

trshd h rdhsjsdrnytjdt jyjyukfddythj

d. is the correct answer

step-by-step explanation: