There is a parallelogram ABCD with diagonals AC and BD. The diagonals AC and BD intersects each other at point E. Side AB is congruent to side CD. If ∠BAC ≅ ∠DCA, the Choose... theorem can be used to show that △ABE ≅ △CDE.

SAS theorem

Step-by-step explanation:

Given

Required

Which theorem shows △ABE ≅ △CDE.

From the question, we understand that:

AC and BD intersects at E.

This implies that:

and

So, the congruent sides and angles of △ABE and △CDE are:

---- S

---- A

or  --- S

Hence, the theorem that compares both triangles is the SAS theorem

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i