Which of the following equations represents a line that passes through the points (10,9) and (0,-6)? I. 3x-2y=12
II. y= 3/2x - 6
- - - - - - - - - - -
1- neither
2- I only
3- II only
4 - I and II only

4

Step-by-step explanation:

I saw karma so i came as fast as I could- welp anyways

Lets test the first equation and coordinate #1 first, 3x-2y=12, and (10,9).

Here we can substitute x as 10 and y as 9, and solve the equation to see if 3(10)-2(9) equals 12 or not.

30-18=12, yep

now lets test the second coordinate, (0, -6). Substitute x as 0 and y as -6, and solve the equation.

3(0)-2(-6)=12

0+12=12, yep

So I definitely works

For II, lets do the same thing

(10, 9) -- 9=3/2*10-6

9=15-6, works

(0, -6) — -6= 3/2*0-6

-6=0-6, also works

So uh therefore I and II both work you see what I mean-

i apologize in advance if i made you more confused than you already are-

correct answer:

a + bi

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°