demand for a gallon of milk is distributed with a weekly mean of 50 and a standard deviation of 15. How much additional milk must be stocked to increase service level from 50% to 80%

answer: none of these answers are correct only the second half is

step-by-step explanation:

ur right ive taken the test

step-by-step explanation:

measurement of the swimming pool is given as = 7 yards 4.79 feet

first we will convert this to yards only.

1 foot = 0.33 yards

so, 4.79 feet = yards

so total yards are = yards

now we will convert this in meters.

1 yard = 0.914 meters

8.580 yards = meters

0.842 m = 0.842*100 = 84.2 cm

this becomes 7 meters and 84.2 cm

hence, the pool is 7 meters and 84.2 cm wide.