AB = x, BC = 4x, AC = 35 Find x and BC 2) AB = 5, BC = 6x + 1, AC = 42 Find x and BC
3) AB = x + 4, BC = 8x – 4, AC = 63 Find x and AB
4) AB = 2x + 4, BC = 6x + 15, AC = 91 Find x and AB
5) AB = 3x – 1, BC = 6x + 5, AC = 3x + 22 Find x and AC
6) AB = 2x – 3, AC = 9x + 14, BC = 8x – 7 Find x and AC
7) AC = 15x , BC = 5x + 14, AB = 3x + 42 Find x and BC

i think the answer would be c

σк тнє αиѕωєя ιѕ (α.)

нσρє ι ¢συℓ∂ нєℓρ υ

perimeter = 10 +  √10  units

explanation:

first, we will need to get the length of each line using the distance formula which is as follows:

distance = 

1- length of ab:

ab =   = 5 units

2- length of ac

length of ac is the same as ab = 5 units

3- length of bc:

bc =   =  √10  units

now, we can get the perimeter by adding the side lengths as follows:

perimeter = 5 + 5 +  √10

perimeter = 10 +  √10  units

hope this : )

read more on -