How do I solve this equation by using the quadratic formula 3x^2-12x-27=-6

Move all terms to the left side of the equation and simplify.

3x²−12x−21=0

Use the quadratic formula to find the solutions.

(−b±√b²−4(ac))/2a

Substitute the values a=3, b=−12, and c=−21 into the quadratic formula and solve for x.

(12±√(−12)²−4⋅(3⋅−21)0/2⋅3 Simplify =>  x=2±√11

The result can be shown in multiple forms.

Exact Form: x=2±√11

Decimal Form: x=5.31662479…,−1.31662479…

Step-by-step explanation:

Step-by-step explanation:

The quadratic equation is

x=−b=−√b2−4ac2a

for a quadratic taking the form

ax2+bx+c=0

So for this equation it is

x=−(−12)±√(−12)2−4⋅3⋅112⋅3

x=12±√144−1326

x=12±√4⋅36

x=6±√33

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.