By using a suitable method find the lowest common multiple of each of the following losts of number g) 9, 12,21

1,3,6,8,12,18,24,27,32,42

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.