The total resistance R for a parallel circuit with three bulbs is R = 1/1R1+1/R2+1/R3. Find the total resistance R of a parallel circuit with bulbs that have resistances of 3 ohms, 2.5 ohms, and 2.5 ohms.

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step-by-step explanation:

then i will answer

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

the diameter is 16 cm. are you a teacher?

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