The data in the line plots show the grade point averages of students in two different classes. Part A
Find the measures of center and measures of variability of the two sets of data.
Part B
What conclusions can you draw from the two sets of data?
A. Students in class A have higher averages than students in class B
B. A student in class A would most likely have a grade point average of 3.0
C. Class B's data have less variability than class A's data
D. The mean and median of class A's data are the same
E. The mean and median of class B's data are the same

10/60

step-by-step explanation:

if you divide 10 by 60 the answer is 0.166666 while if you divide or solve the other problems it equals 0.6

answer: graph 2

step-by-step explanation:

step-by-step explanation:

to determine whether a given function is even, we simply substitute x with -x in the expression. if the result after simplification is identical to the original equation, then the function is said to be even other wise odd.

f(-x) = (-x)^2 - (-x) + 8

      = x^2 + x +8

the resulting function is not identical to the original one;

f(-x) ≠ f(x)

therefore, f(x) is not an even function