What is the equation of the line that passes through the point (1, 3) and has a slope of 6?

Answer (assuming it can be point-slope form):

Step-by-step explanation:

Use the point-slope formula to write the equation of the line in point-slope form. Substitute , , and for real values.

represents the slope, so substitute 6 in its place. and represent the x and y values of one point the line intersects, so substitute the x and y values of (1,3) into the equation as well. Substitute 1 for and 3 for . This gives the equation in point-slope form:

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: