For what value of a does the equation ax^2-3cx-5=0 have 1 as one of its root? PLZ HELP. Will give brainliest

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step-by-step explanation:

the eight graders whould be the answer

step-by-step explanation: could you give me 5 stars

option (a)

step-by-step explanation:

step 1:   take 2 number whose product equal to 25..

and sum of those two number are -10

step: 2 for example here if we take 5,5 are the number,,

5*5=25

and

5+5=10

but we need -10

so if we take   -5,-5

so -5*-5=25

and -5+(-5)=-10

s0

come the equation

replace -10x by these number

like -5x -5x+25

take common

x(x-5)-5(x-5)=0

(x-5)(x-5)=0