The perimeter of a rectangle is 62cm. if the length of the rectangle is 24cm, what is tge width of the rectangle

b= 7

Step-by-step explanation:

here's your solution

=> perimeter of rectangle = 62 cm

=> length = 24 cm

=> let width be (b)

=> perimeter of rectangle = 2(l + b)

=> 2(l + b ) = 62

=> 2(24 + b) = 62

=> 48 +2b = 62

=> 2b = 62 - 48

=> 2b = 14

=> b = 14/2

=> b = 7

hope it helps

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15