Consider three points in the plane, P=(−4,0),Q=(−1,12)andR=(4,32) . Find the equation of the line of the line through P and Q.

In summary, if you are given three points, you can take the cross product of the vectors between two pairs of points to determine a normal vector n. Pick one of the three points, and let a be the vector representing that point. Then, the same equation described above, n⋅(x−a)=0. Hopefully i helped

Step-by-step explanation:

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204