A certain open tube has a fundamental frequency of 410 Hz. What is the frequency of the third harmonic of this open tube? 1.
771 Hz
2. 410 Hz
3. 137 Hz
4. 1230 Hz

18

step-by-step explanation:

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let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

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