Can someone please help me with this. Find the missing length indicated.

Step-by-step explanation:

the little triangle is  1/3 of the big one.  we know that b/c of the  6/18  sides and that's  also 1/3, I mean the fraction 6/18 , reduces to  1/3

so we know that 1/3 of the 42 is the small triangle and that 2/3 of 42 is the rest of that distance,  so  

42 * 2/3  = ?

28 = ?

so that part that they want to know is 28 units...  :)

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

its kind of blurry. can you put a clearer pic?

step-by-step explanation: