In circle O, chords AC BD intersect at E. If m\overgroup{AB} AB =95° and m\overgroup{CD} CD =45°. AE is x+2, CE is x, BE is 5, and ED is 3 in length. m∠AEB = m∠CED = m\overgroup{AD}=m AD = m\overgroup{BC}\ =\m BC = m\angle AED\ =\m∠AED = m\angle BEC\ =\m∠BEC = AE = CE =

answer: it's a

step-by-step explanation:

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560