10 different names are put into a computer, and one of them is Colin, the computer chooses 2 names at random. The computer is set so that the same name can be chosen twice. What is the probability that Colin is chosen at least once?

0.19

Step-by-step explanation:

Given that :

Total possible outcomes = 10

If the same name can be chosen twice, then probability is with replacement ;

Probability = required outcome / Total possible outcomes

Required outcome = number of Collins in name = 1

Probability of choosing Collins atleast once ;

2[P(Collins) * P(not Collins)] + P(Collins) * P(Collins)

P(colins) = 1/10

P(not Collins) = 9/10

2(1/10 * 9/10) + (1/10 * 1/10)

2(9/100) + (1/100)

18/100 + 1/100

19/100

= 0.19

b) 36

step-by-step explanation:

18 times 2 is 36

ok so the answer to your question is simple as long as you look at the different dimensions that contain the exemplary letters that combined in the right order give you words that eventually within the 5th dimension will conform and give you the correct answer to your question. hope i , stop looking at this easily, look at it with a spectral view.

step-by-step explanation:

told you