What is the point-slope form of a line that has a slope of -4 and passes through point (-3, 1)? O y-(-3)=-4(x-1)
O y-1=-4[x-(-3)]
0 -1-,--4-3-xy)
O 3-y,--4(1-x)

B. y - 1 = -4[x - (-3)]

Step-by-step explanation:

Given:

Slope = -4

Point = (-3, 1)

Required:

Point-slope form of the line

Solution:

Equation of a line in Point-slope form is given as y - b = m(x - a).

Where,

a = -3

b = 1

m = -4

Plug in the values

y - 1 = -4[x - (-3)]

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.