A ship sails from port P to port Q. Q is 74 km from P on a bearing of 142º.
A lighthouse, L. is 58 km from P on a bearing of 110%.
(a) Show that the distance LQ is 39.5 km correct to 1 decimal place.

Answer is in the file below

cutt.ly/tz3yDpb

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

answer: 8d

step-by-step explanation:

45+5= 50+5=55+5=60