A shark is swimming 28 feet below sea level. If the angle of depression from a boat on the water is 19 degress. What is the distance between the boat and the shark?

81.3 feet

Step-by-step explanation:

A shark is swimming 28 feet below sea level. If the angle of depression from a boat on the water is 19 degrees What is the distance between the boat and the shark?

We solve the above question using Trigonometric function of Tangent

tan θ = Opposite/Adjacent

θ = Angle of depression = 19°

Distance between the boat and the shark = Adjacent = ? = x

Opposite = 28 feet

Hence:

tan 19 = 28/x

Cross Multiply

tan 19 × x = 28

x = 28/tan 19

x = 81.317904575 feet

Approximately = 81.3 feet

The distance between the boat and the shark is 81.3 feet

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10