PLEASE ANSWER ASAP The Pear company sells pPhones. The cost to manufacture x pPhones is
C(x)= -25x^2 + 49000x +21390 dollars (this includes overhead costs and production costs
for each pPhone). If the company sells x pPhones for the maximum price they can fetch, the
revenue function will be R(x)= -29x^2 + 129000x dollars.
How many pPhones should the Pear company produce and sell to maximimze profit? (Remember
that profit=revenue-cost)
x=

10,000 pPhones.

Step-by-step explanation:

The cost to manufacture x pPhones is given by the cost function:

And the revenue for selling x pPhones is given by the revenue function:

We want to determine the number of pPhones the Pear Company should sell to maximize profits.

First, we can find the profit function. Profit is given by:

Therefore:

Simplify:

Add. So, our profit function is:

Note that our profit function is a quadratic. The maximum point of a quadratic is always its vertex. So, we can find the vertex of the profit function.

The coordinate of the vertex is given by:

In this case, a = -4, b = 80000, and c = - 21390.

Therefore, the point at which profit is maximized is:

Therefore, in order to maximize profits, the Pear Company should sell exactly 10,000 phones.

Notes:

And the maximum profit will be:

answer: 25 is the correct answer

step-by-step explanation:

the answer is d

step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

  -3         -3  

y=-4x+5