Mathematics, 18.03.2021 09:50 aahneise02

Lol please help i literally cannot do math to save my life

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Answer from: Carri425

$\displaystyle d \approx 3.6$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Algebra I

Reading a Cartesian Plane

Coordinates (x, y)

Algebra II

Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Find points from graph.

Point A(-2, 1)

Point B(1, -1)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Substitute in points [Distance Formula]: $\displaystyle d = \sqrt{(1+2)^2+(-1-1)^2}$ [Distance] [√Radical] (Parenthesis) Add/Subtract: $\displaystyle d = \sqrt{(3)^2+(-2)^2}$ [Distance] [√Radical] Evaluate exponents: $\displaystyle d = \sqrt{9+4}$ [Distance] [√Radical] Add: $\displaystyle d = \sqrt{13}$ [Distance] [√Radical] Evaluate: $\displaystyle d = 3.60555127546$ [Distance] Round: $\displaystyle d \approx 3.6$

Answer from: coolmonkey3643

3.6 units

Step-by-step explanation:

Point A --> $x_{1} \\$ = -2 , $y_{1}$ = 1

Point B --> $x_{2}$ = 1 , $y_{2}$ = -1

AB =

$\sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2 } \\\sqrt{[1 - (-2)]^2 + [(-1) - 1]^2} \\\sqrt{3^2 + (-2)^2} \\\sqrt{9 + 4} \\ \sqrt{13} \\3.605$

distance between AB can be rounded to 3.6 units

Hope it helps.

Answer from: Quest

assuming this is from a math graphing problem.

7 would be on the x-axis which is the horizontal line on the graph

84 would be on the y-axis which is the vertical line on the graph

Answer from: Quest

if the rectangular pool has a area of 192 square ft. and length of 15 ft. you must divide 15 into 192. 192 ÷ 15 = about 13 ft.

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