Help pls if u can pls

Infinite solutions.

Step-by-step explanation:

Let's solve your system by substitution.

3y=9x+15;3x−y=−5

Rewrite equations:

3x−y=−5;3y=9x+15

Step: Solve 3x−y=−5 for y:

3x−y=−5

3x−y+−3x=−5+−3x(Add -3x to both sides)

−y=−3x−5

−y   −1   −1=−3x−5

(Divide both sides by -1)

y=3x+5

Step: Substitute 3x+5 for y in 3y=9x+15:

3y=9x+15

3(3x+5)=9x+15

9x+15=9x+15(Simplify both sides of the equation)

9x+15+−9x=9x+15+−9x(Add -9x to both sides)

15=15

15+−15=15+−15(Add -15 to both sides)

0=0

Hello lucker

6.5

step-by-step explanation:

you said it was in the question

~courtney

ummm seems that u didnt post the attachement !