In ΔOPQ, o = 500 cm, p = 600 cm and q=380 cm. Find the measure of ∠P to the nearest 10th of a degree.

84.8°

Step-by-step explanation:

a²+b²+c²-2bc(cosA)

cosA = b² + c² - a² / 2bc

That is the formula we will be using.

Then, plug in our numbers.

cosP= 500² + 380² - 600² / 2(500)(380)

cosP= 34400/380000

cosP≈ 0.09052631

cos⁻¹(0.09052631) ≈ 84.81

∠P = 84.8°

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: