Can you help me solve for x?​

the answer is a

step-by-step explanation:

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation:

using the formula for pythagorean theorem (a2+b2=c2)(the twos are exponents), and knowing that you have b squared and c squared, just reverse it. 26 squared minus 10 squared equals c squared. 26 squared is 676 and 10 squared is 100. you get 576, then use your square roots to undo the squared numbers to get 24.

answer:

the product of -35 and -625 is positive.