Triangle ABC with vertices A (-1, 2), B (-1,-2), and C (-4,-2) is dilated by a scale factor of 2 to form triangle A'B'C'.

What is the length, in units, of side A'B'?
units

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step-by-step explanation:

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5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116