When 2 dice are rolled, find the probability of getting a sum greater than 8.

10/36

When a pair of fair dice are rolled , the total possible cases are (6 × 6) = 36. Out of these 36 cases the following 10 cases are favors(giving the sum > 8) for the happening of the event . These 10 cases are (3, 6), (4, 5), (4, 6),(5, 4), (5, 5), (5, 6) , (6, 3), (6, 4), (6, 5), & (6, 6)

Step-by-step explanation:

6×6=36 possible outcomes and only 15 possible outcomes summing 8 or more than 8.

Since there are six possible outcomes, the probability of obtaining any side of the die is 1/6. The probability of rolling a 1 is 1/6, the probability of rolling a 2 is 1/6, and so on.

okay wait before i answer, is this for your points on a graph?

step-by-step explanation:

this is not a question