In a javelin throw competition, five athletics score 56, 58, 63, 57 and 61 meters. What are their Mean and Median?

Mean = 59

Median = 58

Step-by-step explanation:

Given the data for a Javelin throw :

56, 58, 63, 57 61 meters

Reordering the data: 56, 57, 58, 61, 63

Mean, m = Σx / n

n = sample size = 5

m = (56 + 57 + 58 + 61 + 63) / 5

m = 295 / 5

m = 59

The median : 1/2 (n+1)th term

1/2(5 +1) the term

1/2(6) = 3rd term

Median value = 58

answer: ♡♡♡♡♡♡♡♡♡♡

step-by-step explanation:

3

step-by-step explanation:

because where the point where the 2 lines intersect is (3,-1) the x value is 3