For time t≥0 , the acceleration of a particle moving along the x-axis is given by a(t)=cost+t. At time t=0, the velocity of the particle is 8 and the position of the particle is 0. What is the position of the particle at time t=π4 ?

idk the answer but just put a

step-by-step explanation:

step-by-step explanation:

f(x)=2x^2 -1 

translation is a function transformation that transform the function in a way of translating. by translating the function its graph is moved  up an down. moving the function f(x) 2 units to the left will be the new function g(x) with the equation: g(x)=f(x+2)=2(x+2)^2 -1

circumference divided by 3.141592654 then timesthe radius twice

step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice