A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the
maximum height reached by the rocket, to the nearest tenth of a foot.
y = -16x2 + 136x + 57

Maximum height = 346 feet

Step-by-step explanation:

Given that,

The height of the rocket, y in feet, is related to the  time after launch, x in seconds, by the given equation as follows :

.....(1)

We need to find the maximum height reached by the rocket. For maximum height,

Put dy/dt = 0

So,

No, put x = 4.25 in equation (1).

So, the maximum height reached by the rocket is equal to 346 feet.

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step-by-step explanation:

7,24

step-by-step explanation: