Apolynomial has one root that equals 2+i. name one other root of this polynomial.

The other root is 2-i.

Step-by-step explanation:

First, we need to make an assumption: the polynomials has real coefficients. Otherwise, the polynomials can be P(x) = x-2-i = x - (2+i), which has complex coefficients, and has only one root. Then, the next reasoning is completely valid assuming that the polynomials has real coefficients.

Polynomials with real coefficients can have complex roots, and the simplest example is P(x) = x²+1. Now, the interesting fact is that those complex roots come in conjugate pairs. Notice that i is a root of x²+1, but -i is also a root.

So, if 2+i is a root of certain polynomials, its conjugate is also a root of the same polynomial, i.e. , 2-i is also a root.

there would only be 50 odd numbers between 1 and 100 so therefor there would be 50 even so that would only be 50 odd numbers.

answer: 0.26

i used the calculator on google