ANSWER ASAP GIVING BRAILIEST AND STUFF! Please answer the following essay question:
Suppose each dimension of a cube is increased. What happens to the surface area when each dimension is doubled, tripled or, quadrupled?

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Step-by-step explanation:

Surface area of a cube = 6a²

When each dimension is doubled,  Side =2a

Surface area = 6*(2a)² = 6 * 4*a² = 4*(6a²)

So, when each dimension is doubled, surface area is 4 times of the original surface.

a = 3a

Surface area = 6*(3a)² = 6 * 9 *a² = 9 *6a²

                     = 9 times the original area

a = 4a

Surface area = 6*(4a)² = 6* 16 * a²

                     = 16 * (6a²)

                     = 16 times of original area

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step-by-step explanation:

2. angles qrt and qst both measures 156 degrees.

step-by-step explanation:  

we have been given a diagram of a circle and we are told that measure of arc qvt is 156 degrees.  

we can see from our given diagram that angle qrt and angle qst subtends to arc qvt.

since we know that angles subtended by the same arc at the circumference are always equal.

by angle subtended by same arc theorem, measure of angle qrt and angle qst will be equal to the measure of arc qvt.

therefore, angles qrt and qst both measures 156 degrees and 2nd statement is the correct choice.