Please help me with these will give Brain

1. EH = 13, 2. x = 70

Step-by-step explanation:

1. Since the triangle here is a right triangle, you can use the Pythagorean theorem: a^2 + b^2 = c^2 (where c is EH, a is BE, and b is BH)

plug in the numbers to get: EH^2 = 5^2 + 12^2

work it out: EH^2 = 25 + 144 = 169

take the square root of each side: EH = 13

2. I'm not exactly sure how to explain this one, but I just took the average of the two angles (112 and 28) and got 70 degrees.

Since x corresponds to the 112 angle on the one side and 28 angle on the other side, I figured that if you move the cross in the middle to where it's at the circle's center, the x angle would equal the new 112 and 28 angles. So I got the average of those two and it was 70.

You'll just have to trust me on this one lol.

560

step-by-step explanation:

giggidy

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841